Transversal reinforcement calculation - Example


We consider a column with a 0.3 x 0.4 m rectangular section and a 3.10 m height. The concrete class is 25/30. The loads on the column are the following:



Top loads


Bottom loads






The shear verification is done according to article 6.2 of EN1992-1-1.

The sizing combination for the shear verification on the X direction is:

Combination 104 : +1.35x[1 G]+1.5x[2 Q]

Design shear force VEd = 135 kN

The shear verification is accomplished if the following relation is satisfied:

VRd ≥ VEd

VRd = min (VRd,max; VRd,s)



αcw = 1.2

bw = 0.40 m

z = 0.9 × d





Since, in the design phase, the real d’ is not known, the program will use in the calculation of the concrete cover from the Concrete cover dialog:


Concrete cover



In the initial stage, the calculation will be done using the value from the viewport. After a certain number of iterations, a longitudinal reinforcement area and a transversal reinforcement area with specific diameters will result.





In the final stage, the calculation is done again with the real d’ obtained as:


The report will reflect the final stage, with the real value of d’.

the real value of d


The value of Ɵ can be defined in the Design Assumptions dialog, Transversal Reinforcement section (Strut slope).


Compression strut angle





The program verifies if:



If not, the spacing sreal is decreased or the transversal bars diameter is increased until the relation is verified.


Main reinforcement


Top section


Asw formula